๐Ÿ’ while loop in java (blackjack) - Stack Overflow

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I am trying to code a simple blackjack game with no suits or anything. Just for number while ("y".equals(playAgain)) Lots of code that does lots of things in loops that have been nested lots of times is the WORST. Wait for it.


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calls "displayInstructions" to tell the user how blackjack works: do /* do while loop to loop playing blackjack Java Program to find Sum of Elements in an Array.


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Exercise Write a program that let's the user play Blackjack. Let money = while (true): Input the user's bet if the bet is 0: Break out of the loop User plays.


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I am trying to code a simple blackjack game with no suits or anything. Just for number while ("y".equals(playAgain)) Lots of code that does lots of things in loops that have been nested lots of times is the WORST. Wait for it.


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I've tried to take the Blackjack game a little further, adding the ability to identify suits and specific face cards. while loops can lead to infinite loops, so be careful. Well JS is my first language (fair experience only in java and visual basic) and.


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Answer to I need a very simple java code that plays blackjack and has a while loop. aces must be able to change between 1 and 11 t.


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blackjack java while loop

We're switching to CommonMark. See my edit to the first block of code in my post. Mena Mena I am not familiar with a switch statement. I am trying to program a basic game of Blackjack. Active Oldest Votes. See edit, also read The recommendations made by Mena. The Overflow Blog. This is because your code for handling your stay choice is now in your code for hit choice, look at the logic. What posts should be escalated to staff using [status-review], and how do Iโ€ฆ. I don't see where choice is being changed from within the loop. Everything you have said here has really helped. For example if the player chooses to hit on their first turn, it works, but on their next turn I can not get the program to allow input. Also, you should catch InputMismatchException s for unexpected input types, and allow the user to get out of the loop. JohnMark13 JohnMark13 3, 1 1 gold badge 10 10 silver badges 26 26 bronze badges. Your use of the break statements means that your loop performs a very limited function, more like an if. Question feed. If choice is 1 it can never be 2 in the same block of code. Currently this is not the case so your program with just add cards every time as you don't check what the user has chosen. Related Hot Network Questions. It would be great if you could explain the concept. Edit in original post. The program will keep adding cards as all your card handling code needs to be in the following condition. For every iteration of the loop you need to make sure you get correct input each time and only if they choose to hit get a card. Featured on Meta. Java Devil Java Devil 9, 7 7 gold badges 28 28 silver badges 41 41 bronze badges. Either store the cards in a list, or keep a cumulative score. Thank you!. Asked 6 years, 9 months ago. Why the developers who use Rust love it so much. This is the revised code I have. I am not sure your program is breaking the way you think it is. This is because in every if statement you break from the loop and do not enter it again. The only issue I am having now is when the player chooses to stay 2 ,the program still picks cards until it busts. Also, I'd strongly recommend using a switch statement to categorize the Integer from the user, instead of the messy if-then-else. The problem I am having is I can not get the program to allow input after the first choice within the loop. Sign up using Email and Password. This time when I choose to stay nothing is output at all. You have a lot of repetition, consider using a switch case on guess3 where 1 outputs the Ace statement 2 through 10 are all the same so, no break statements 'System. Sign up using Facebook. Viewed 2k times. My teacher does not really explain things and tells us to google it. This is my first year taking a programming class. Learn more. Email Required, but never shown.

Stack Overflow for Teams is a private, secure spot for you and your coworkers to find and share information. Sign up or log in Sign up using Google. On breaking out of the loop you have no more code to run.

If your loop worked your use of answer and hand variables means that you would never get a correct value each time around the loop just adding the original two values to the third value. Stack Overflow works best with JavaScript enabled.

Doesn't it explain enough for you? Post as a guest Name. Your problem is that you are literally taking the user's input only once. If you google "java switch" you'll find this page right on top. Visit chat. What you need is a looping condition which is true until either the player busts or chooses to stay and don't break from the loop in every if statement, instead i think you might want to use continue. Podcast New tools for new times. Active 6 years, 9 months ago. Altogether I would recommend: using the infinite loop as per above using Scanner nextLine instead of Scanner nextInt getting a String as a result checking for something starting with "q" or such like for the user wanting to quit otherwise, attempting to parse an Integer out of the String with Integer.